Python askopenfilename get directory xlsx in the same directory – Jane. Tk() def openfile(): path = filedialog. The first thing you must do is compute this file's path. net webpage. However, I if you always select file to append (but you newer create new one) then you could use askopenfilename but it will display button "Open" instead of 'Save` (you can set window title="Open to append") . getcwd() # will get current working directory If you're looking to set up a GUI to ask the user to select a file, use: Try sys. initialdir: This option tells the dialog box what directory to start in, so the box pops up what directory you want to be showing, so you should go with this option. py *. lower time to grasp intention) than the other answers to date, and readability is (usually) king. I use the similar way but it does not work with Mac if I change to this: import os import tkinter as tk # if using Python 3 import Tkinter as tk # if using Python 2 Let's say that your button has been defined. The result of Tkinter's filename = filedialog. askopenfilename(), but is there a way to let the user search for a directory instead of a single file? The Python Tkinter filedialog module offers you a set of unique dialogs to be used when dealing with files. With listdir in os module you get the files and the folders in the current dir. filedialog module. I have a text editor made with Python and tkinter. Tkinter has a wide variety of different dialogs, but the ones in filedialog are specifically designed for file selection. 5. You can rate examples to help us improve the quality of examples. I'm making a program that you use the askopenname file dialog to select a file, which I then want to save the directory to a string so I can use another function (which I already made) to extract the . On Unix and Windows, return the argument with an initial component of ~ or ~user replaced by that user‘s home directory. askopenfilename() test I need to get the selected path within a Filedialog tkinter but I do not know how to because when choosing the path directly in the graphical window save as there is no way to extract the path to s Conclusion. 6. I think os. Tk() root. I'm using threads in other parts of the application to run background processes, but I've just tried running the Tk window in a separate thread and now I get a white rectangle being displayed (which freezes, and I then have to kill). This article covers file-handling topics like opening a file using the askopenfilename method, saving the file using the asksaveasfilename method, and selecting a directory using the askdirectory Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company You should use the os. from tkinter import * Python askopenfilename - 60 ejemplos encontrados. I know the command filedialog. python. Python Locating the file path. On some OSes like windows, it means that you don't have to os. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; I have a simple script which parses a file and loads it's contents to a database. Here's some basic code to resize the window, to illustrate how this would work: import win32gui win = I'm doing a small project in Python and I would like to browse a file or directory to get their path. Thank you. How to open a Tkinter askopenfilename dialog compatible with Python 2 and Python 3. Since all variables are gone when the script finishes it must be something python is pulling from windows itself. The os. Hot Network Questions os. 2. So first, we Explore file dialog boxes in Tkinter: askdirectory(), askopenfilename(), askopenfilenames(), asksaveasfilename(), and more. Right now I'm setting that value as the documents folder but I would prefer to use the last selected folder. If you want to choose a file path use askopenfilename. For example, I want two options, a zip and a folder FileTypes option in my askopenfilename statement. askopenfilename() print(os. py, and the script is run on their machine from this folder, how can I ensure the file dialog will open with this folder to select the . Having written it, I think this code is more readable (i. The way to answer your question is to put something like tkinter askopenfile into a search engine; and if you don't understand what is written there, you should try asking somewhere like Reddit or Quora unless you have a specific question with a code Installing the tkfilebrowser seemed much too much effort just for testing as, according to the documentation, I wouldn't get a mix of files and directories either. When I choose a file to be opened, I do: Get a file's directory in a string selected by askopenfilename. askopenfilename() return path Button(root, text = "click to open the stock file", command=openfile). askopenfilenames() to filedialog. Instead, check what the current working directory is before the change, and save it in a variable; then it will be possible to change to that directory later. Related course: Python Desktop Apps with Tkinter . Failing approaches path = os. 3. If the script directory is not available (e. The code currently using a entry dialog which lets me put in a file name manually. stack() # get info about the module that has invoked this function # (index=0 is always this very module, index=1 is fine as long this function is not called by some other # function in this module) frame_info I would like to get file path as input in my Python console application. resolve() For the current working directory: import pathlib pathlib. Stack Overflow. For example, The desktop is just a subdirectory of the user’s home directory. The askopenfilename() also supports other useful The easiest way to let a user choose a file is with askopenfilename(). destroy() # This is the very last line in my main script. var), in that case, allowing the user to select more than one file at a time may result in exceeding the value of I want the user to pick a file from file explorer and get its path into a variable, ex: filepath = " C\User to filedialog. cwd() doesn’t work in this non-standard environment. askopenfilename iteration. I'm not aware of a fix since then, and the issue has not been marked as closed/resolved. I am a MATLAB user and trying to find something similar to uigetfile. – This is actually a bug on the Windows version that has been present since around the 2. However this listing is directly dependent on the FTP server's way of formatting the list. Return filepath of file from tkinter filedialog. To extract the directory from a path use os. if the interpreter is invoked interactively or if the script is read from standard input), path[0] is the empty string, which While their is no built in way to really do this in tkinter, you could ask the user to select a file using tkinter. but i cannot get the file by using this function note : game_entry return the file directory note : the reason i dont use the filedialog. For loading, I know I have to use scipy. This way the code will work on multiple platforms (Windows/Mac/Linux) For example. askopenfilename() in tkinter. Improve this question. jpg I from tkinter import filedialog as fd import os filename = fd. pathlib. Commented Mar 7, 2016 at 11:49. May I know how can I modify the code to open jpg and pdf file, or other file types? I'm writing a program that just has a browse button to search for a file and then opens the file you select. 1. I'm using Tkinter and I was abble to find only a file browser: filename = tkFileDialog. Use AppleEvents to give focus to Python. path. These are the top rated real world Python examples of tkFileDialog. For example, when I do the following: import sys print sys. splitlist(filez) I have a file dialog to open a file, however, the file that I want to open is in a different directory than the program I wrote. path = os. . tkinter. initialdir is only for the directory. photo = my_image before you pack the label. askopenfilename. The difference is that it returns file entries not names. name. read_excel(label) Access name of chosen directory in python with Tkinter. Eg: Saving f. All of them are methods calls. askopenfile() to get a file's path, so when I choose the file and print its path, I want to get D:/GitHub/repo/test. sleep(10) the dialog windows stays open while python waits 10 seconds. This is everything Tk related in my code. Skip to main content. arr = os. basename. Path(__file__). asked Access name of chosen directory in i use entry and use filedialog. Indeed, starting the window in the main Flask thread locks up the rest of the application. Note, if you use the last option, to get the full name from an open file f, use f. This is my 'open file' method: def onOpen(self): of course, isn't very nice. filedialog. write file to same directory as the askopenfilename was found. path because your program will be cross-platform: currently, your solution would not work for Windows. sourceFolder = '' main_win. I have the following code It looks to be having an issue getting the icon from whatever directory I am in. from tkinter import filedialog from tkinter import * from shutil import copy2 import os root = Tk() root. However, only one file can be selected. I am using Anaconda/Spyder to give the user a choice to select a file (through a dialog box). One "Browse" to open file, Python-Tkinter-askopenfilename: Use filepath of the opened file for reading values. What I was trying to achieve is for Entry either to contain the default text given by status or to print the output from the askdirectory command, once the user has selected the directory. In that case I would use the first or last option. I'm in python 3. It creates the Filename. Because the latter is not fixed, I have been reading and experimenting to find the proper way to remove the path of a file when selected using filedialog. 9. pack(pady=20) file_path = Import os from tkinter import filedialog import tkinter as tk from zipfile import ZipFile root = tk. A good answer here could be easily copy-pasted and :return: Project root directory name """ # stack trace history related to the call of this function frame_stack: [FrameInfo] = inspect. Remember that you are answering the question for readers in the future, not just the person asking now. Allow the user to select a directory. For the directory of the script being run: import pathlib pathlib. Calling this will open a modal file picker dialog, blocking other app interaction until the user selects a file or The askopenfilename function is used to initiate an open file dialog in Tkinter. withdraw() self. join function will let you do that by joining parts of the path (the directory and the file name): askopenfile returns a file handle, not a file name. askdirectory(parent=root, title='Open file to encrypt') It creates the FileName. askopenfilename() and then use os. For example: import os from contextlib import contextmanager glob is useful if you are doing this in within python, however, your shell may not be passing in the * (I'm not familiar with the windows shell). dirname Python askopenfilename - 60 examples found. It is only window with two buttons. I want it to close immediately after file Python tkinter askopenfilename() not opening and responding. import os cwd = os. Or, just use the already open file that askopenfile returns. For the file name itself you need to use initialfile. askopenfilename() Code language: Python (python) The askopenfilename() function returns the file name that you selected. Follow Tkinter is a python interface that is used to access the Tcl/Tk GUI toolkit that python uses to build desktop GUI applications. I need to get the path from the GUI and assign the path to my main code. Now I am having trouble displaying it, even though I get the directory dialog and it is clickable. I thought askopenfilename() will only return the name of the file, so I just ignored this function. path module. Path. Default file type in tkFileDialog's askopenfilename method. From that we can get the directory using either pathlib or the os. Sorry if this a repeated Question. askopenfilename(filetypes=[("Excel files", "*. select a specific file, choose a directory, save a file to a specific directory. Otherwise, the initial directory is the personal files directory of the current user. os. Just add this line: my_image_label. withdraw() file_path = filedialog. Below is my code: Stack Overflow is not intended to replace existing tutorials and documentation, and is not a discussion forum. That way the user can either type the directory location in the Entry box, or fill the entry box automatically by I am using tkinter asopenfilename to trigger a file chooser so as to read files from my local directory. x. You can open a It may be hard for novice python programmers to really get used to using list comprehensions for filtering, and it can have some memory overhead for very large data sets, but for listing a directory and other simple string filtering tasks, list comprehensions lead to more clean documentable code. Improve this answer. askopenfile. I know that this is possible in C#, yet I'm new to Python and don't know if this is possible here too, preferable platform-independent (Windows, Ubuntu). Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company In my script I want a dialog to pop up in which the user can . I have a matrix saved in another folder. python open a . Upon choo askopenfilenames returns a string instead of a list, that problem is still open in the issue tracker, and the best solution so far is to use splitlist:. This works fine, except for some reason on Windows it's giving me forward slashes. You can't pass a file handle to open. Python Help. basename i try to get the excel path from Tkinter with askopenfilename. askopenfilenames extracted from open source projects. askdirectory() file_name = "test. expanduser(path) to get the user's home directory. dirname(__file__)) Since Python 3. This is my query. However it does get past this and continue to run the code after it. I need to get the file_path from the GUI and assign it to Workbook = ExcelAppl. split you should always have a non-empty directory portion and file-name portion. Perhaps you could use a dictionary; the keys being the filenames and the values being the respective file contents. filedialog standard module. To read an open file, use f. askopenfilename(initialdir=os. I've tried the answer from this post: Tkinter askopenfilename() won't close no luck. Or you will have to create own dialog. realpath(__file__)) (Note that the incantation above won't work if you've already used os. txt"): txtfiles. When I select the file (mp3) from the folder I can use a print statement to check the value of the variable, which g I found this question earlier: Browsing file or directory Dialog in Python. resolve() Python 2 and 3. Thanks ! In a part of my code, I am going to get the directory of files from user. In this article, we will explore the Im trying to copy a file which is selected using a dialog window to a relative directory. io. import glob txtfiles = [] for file in glob. On Unix, an initial ~ is replaced by the environment variable HOME if it is set; otherwise the current user’s home directory is looked up in the password directory through the built-in module pwd. Python tkinter askopenfilename not responding. :param start_directory: The starting directory path. org Tkinter filedialog issue. user122244. askopenfilename extraídos de proyectos de código abierto. Follow edited Jun 14, 2018 at 15:20. Python 3. Get a single file path with askopenfilename (title, initialdir) askopenfilename can get the selected file path as a string. askopenfilename will ask what file I want to search and the f. and I want to ask the user to chose the matrix then I get its directory and load it. I searched and found a question filedialog, tkinter and opening files. The askopenfilename() and askopenfilenames() functions display a dialog to open one or more files. 4. It is pretty obvious that I'm pretty new to python and I am trying to make a simple GUI with tkinter that would have two buttons. dirname(sys. import tkinter from tkinter import messagebox from tkinter import filedialog main_win = tkinter. Tkinter python filedialog. Actually, os. Whatever file you pick is automatically opened and the handle is returned. Why import os def get_sub_directory_paths(start_directory, sub_directories): """ This method iterates through all subdirectory paths of a given directory to collect all directory paths. luvnrocs (Jenn Morris) November 3, 2023, 9:41pm 1. write will save the results into a file. About; Selecting a file from a stated directory in Python. 8 and if directory is empty I don't get an exception but simply an empty list [] What I'm trying to do: User chooses two files using the two 'open file' buttons; File paths of chosen files are displayed so the user can review and change if need be Static factory functions. getcwd(), title="Select file", filetypes=[("zip", "*. While working with GUI one may need to open files and read data from it or may require to write data in that particular file. Which type you need really depends on your applications needs. askopenfilename I found this code online that open a file and show it is tk window. To get the full path to the directory a Python file is contained in, write this in that file: import os dir_path = os. python file dialog accessing file name. My problem is that after the file is chosen, the window freezes and python is 'not responding'. read() (returns a string). :param sub_directories: A List that all subdirectory paths will be stored to. how can i get the folder names existing in a directory using Python ? I want to save all the subfolders into a list to work with the names after that but i dont know how to read the subfolder name Get early access and see previews of new features. I'd put filetypes=[('Zip File', '*. askopenfilename(). f_picked = tkFileDialog. filename = fd. I'm using sourceDir = filedialog. askdirectory() and user could navigate through directories. 6 release of Python. There is no actual trace of the "time created" in most OS / filesystems: what you get as mtime is the time a file or directory was modified (so for example creating a file in a directory updates the directory's mtime) -- and from ctime, when offered, the time of the latest inode change (so it would be updated by creating or removing a sub-directory). Use tkFileDialog. example to list a directory and print files bigger than max_value bytes: Thanks. Is there a simple way to let the user select either a single file or a directory in tkinter from a common dialog ? I know there are the askopenfilename() and askdirectory() methods, but is there a simple way to combine the two ?. import tkFileDialog tkFileDialog. select multiple files. And as expected of I'm trying to get a filepath with askopenfilename() ask the user for files directory and then run a script. That's a serious mistake I have made. The most important ones are: askopenfilename() / askopenfilenames() askdirectory() asksaveasfilename() Hello, Welcome to Stack Overflow! While this code may answer the question, including an explanation of how or why this solves the problem would really help to improve the quality of your post. withdraw() root. import Tkinter,tkFileDialog root = Tkinter. What I want to know is how I can access certain files using Python's file functions. I want to set my initialdir to a KNOWNFOLDERID like Documents or Desktop. Tkinter Filedialog. asksaveasfile That will return a directory instead of a file name. I'm trying to get a function that would run and also return the result in a variable y. askopenfilename() python; tkinter; Share. Get file path from askopenfilename function in Tkinter. askdirectory() does the same for browsing a folder (it is not possible to select more than one folder). askopenfilename(parent=root,title='Open file to encrypt') or only a directory browser: dir = tkFileDialog. join method to join paths rather than a simple + string concatenation. So, I've written a small (relatively) function, using just Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Is it posible to use that function and also se what´s inside the folder that i want to select the directory from? Because now when i use the function i can open the explorer and get the directory path to the folder i need but i can´t se what the folder Otherwise, if lpstrInitialDir is not NULL, it specifies the initial directory. Python askopenfilename - 60 examples found. Python Tkinter get result of askopenfilenames() Solution1 (as per your needs - when files can be in different locations) Things to note: I changed filedialog. The tkinter filedialog comes in several types. Why can't I change the current working directory? See more linked questions. I am trying to create a typical "select files" section in my GUI (tkinter) where I person can enter a path to file or search for it. askopenfilename(initialdir = "/",title = "Select file",filetypes = (("text file Skip to main content. csv_path = tkFileDialog. It works fine with one filetype in this way: filedialog. Python Version: 3. The cross-platform way of getting the name of the directory you're in would be. How can I get folder where is stored file selected from tkinter filedialog? I want make something such this: from tkinter import filedialog as fd filename = fd. – This function will display file types and their respective extensions at the bottom of the dialog, helping users to filter their file choices. askopenfilename(), as described in a tkinter. Get the Python Script location using os. from tkinter import Tk from tkinter import filedialog import os root = Tk() root. cwd() will always work in that it will always obtain the current working directory. The problem is that the current working directory (i. exe" Static factory functions. You can't "open" a directory using the open function. I am totally new to Python, there might be some stupid mistakes. This function is meant to be used to open files. Python: Get file path from a text file. file dialogs tkinter filedialog. askopenfiles (mode = 'r', ** options) ¶ The above two functions create an Open dialog and return the opened file Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I am trying to use tkinter. scandir. Estos son los ejemplos en Python del mundo real mejor valorados de tkinter. One can achieve this with the help of open() I am running this script in Python to find a certain line in a file. The class below do this task: Inside this method, we got to pass a bunch of different options. If you want the file name, use askopenfilename instead of askopenfile. Tk() filez = tkFileDialog. I would like a quick and easy way to present a file selection dialog to the user, they can select the file, and then it's you will have to create GUI for this. zip'), for a Zip file but what do I put for an actual directory or folder? I am trying to use a tkinter filedialog. isdir/file to know if it's a file or not, and that saves CPU time because stat is already done when scanning dir in Windows:. The below functions when called create a modal, native look-and-feel dialog, wait for the user’s selection, then return the selected value(s) or None to the caller. And if you just want to get the directory name and no need for the filename coming with it, then you can do that in the following conventional way using os Python module. realpath() can be used to get the path of the current Python script. withdraw() current_directory = filedialog. command line steals focuse from tk window. askopenfilename because i want to get dif file extension in the same folder so it will be convenience if just know the Discussions on Python. tk. Workbooks. I'm using python 3. listdir('c:\\files') with glob you can specify a type of file to list like this. However, I wish to use the Skip to main content. Also, Tkinter python filedialog. I would like python to find the current user's username and then implement it into the following line of code. Commented Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I have a gui which initializes the askopenfilename when a button is pressed but I want to be able to account for when the user selects cancel on the askopenfilename dialogue Here Using python 2. withdraw() data_file_path = askopenfilename() # other code with prompts, mostly print statements Tk(). argv On my shell, I type: $ python test. But it only allows me to open the png file. 5, you can use os. dirname(os. If lpstrInitialDir is NULL and the current directory contains any files of the specified filter types, the initial directory is the current directory. Some clues can be found here, this code can be 'translated' to Python using the pywin32 module. Python-Tkinter-askopenfilename: Use filepath of the opened file for reading values. askopenfilename() and pd. path contains lots of useful path manipulation functions. Here, what you want to do is open the file that's in the directory. To streamline the process, consider using a context manager to reset the path automatically after a temporary change. To quote from the Python docs: As initialized upon program startup, the first item of this list, path[0], is the directory containing the script that was used to invoke the Python interpreter. filename = filedialog. I also want to resize the image I select, but do not really know how to put the code into the frame. 11. Python Tkinter get result of askopenfilenames() 1. import tkinter as tk from tkinter import filedialog root = tk. This functionality in Tkinter is an extension of the askopenfilename function available in Tcl/Tk. See code below. select multiple files using glob in python. It doesn't work. xls file one a smb server. txt without knowing the absolute path? from Tkinter import Tk from tkFileDialog import askdirectory, askopenfilename root = Tk() root. I want to use that directory for my initial local_path entry widget. 3 and Windows XP 32 bits I get the following output selecting 2 files: If you add time. expanduser(path) could be helpful. extraction of file from filepath. ; Tk(). askopenfilename() appears to always be a full path name of an existing file (this is based on a quick experiment, not any documentation; the documentation appears to be a bit thin), so that after os. I tried this code but every time I run the module it appears a blank window in the back of the dialog box and normally after I select the directory it should disappear but it still remains in the background and only if I close it manually it stops. dirname() on the file selected to get the directory the file was selected from, effectively returning both a file and also a directory, all from the same dialog. realpath() Method . I wish to save the filepath we get from filedialog() in a variable outside the defined function openfile(). I think you're looking for os. txt and . askopenfilename extracted from open source projects. Get a file's directory in a string selected by askopenfilename This is what I use in my code so it will work with the Tkinter module in both Python 2 and 3: try: import Tkinter as tk import ttk from tkFileDialog import askopenfilename import tkMessageBox import tkSimpleDialog from tkSimpleDialog import Dialog except ModuleNotFoundError: # Python 3 import tkinter as tk from tkinter import ttk from Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I want to get path of file "exportFile". xlsx")]) Share. 7. tkinter In the XFS file system, does the ls command (syscall getdents) access the disk, or is there a cached directory structure in Hello! As the title suggests I need some help regarding an "open directory" dialog box. 3 or OSX 10. g. 1 and tcl/tK 8. abspath(os. The file dialog opens to the directory where I am. 7? Edit: Forget anything I said. askopenfilename() method to be able to select image files for a generator. TextIOWrapper Skip to main content I guess the idea is to parse the results to get the directory listing. This is not directly supported. The function returns fine and the code below displays the file name okay but the dialog window doesn't close immediately after hitting 'open' or 'cancel', it freezes. UserFileInput needs to return w so that I can use the output of the function later on. Open('excel file path'). Get early access and see previews of new features. Finally you can create two scripts - one with askdirectory and one with askopenfilename and run it separatelly. Python 3 - Tkinter - askopenfilename - Filter filenames trough regEx (Not by extension) How to check file extension of selected file through askopenfilename in python. Setup: Windows 7. askdirectory to get the folder name. withdraw() drug_library_path = askopenfilename() Once the code reaches the first two lines of code, the command line just sits with a blinking cursor, like it's waiting for input (my guess, for askopenfilename() to return a file location), but nothing happens. A google search failed me. sourceFile = '' def chooseDir(): I would like to select an image from the directory and resize it. Is there a universal approach in Python, to find out the path to the file that is currently executing?. Picture won't open in File Dialog, Tkinter, Pillow. zip")]) And used the ZipFile and namelist to On Windows, the FolderBrowserDialog function seems to be used, which can't be resized easily, although it probably can be resized with some effort. This function will display file types and their respective extensions at the bottom of the dialog, helping users to filename = fd. What I would like to do is to expand this so that when the program pops up the file directory window, filedialog. For the directory of the script being run: I have a script that opens a prompt window for a user to select a directory before performing some other tasks. glob("*. geometry("1000x500") main_win. askopenfilename() to get just the file name itself. Python tkinter askopenfilename I've just started working with GUIs in python 3 using TKInter, and I simply want to open a file, read it and write some columns of it on another excel file, so I created a method for asking the route of the file that I want to read: List directory tree structure in Python? We usually prefer to just use GNU tree, but we don't always have tree on every system, and sometimes Python 3 is available. I should try it out first. But if I call askopenfile and askopenfilename the user has to use the 'open file' dialog twice. Follow How to access a desired path with filedialog. if the second is chosen I want that path to be shown in the entry box. In Python how do you use filedialog. askopenfilename() Use the askopenfilename() Method to Open the File Dialog Box in Tkinter. unpythonic. parent. Here is some sample code which will get the current directory: curr_directory = os. To do this there is an Open Button and Entry bar which shows the address like the picture below: Open Button is bound to filedialog. askopenfiles (mode = 'r', ** options) ¶ The above two functions create an Open dialog and return the opened file I'm writing a python script that uses tkinter to open a "open file pop up" using the code root. path[0]. To get started we need to make sure Tkinter is I'm not sure what im doing wrong in my code (below). Is there any other file dialog that can do. After the get path and read Reading excel file with pandas in python how to fix : FileNotFoundError(2, 'No such file or directory') 3. askdirectory(title="Select csv directory",initialdir=default_initial_dir) print csv_path And I have the following behaivours in different computers: In one computer, with Python 2. Python askopenfilenames - 60 examples found. I would like whatever askopenfilename would return. append(file) Get early access and see previews of new features. The askopenfilename() is responsible for opening and reading files in the Tkinter GUI application; this method exists in the filedialog class. tkinter - retrieve file name during askopenfile. Python Opening files in a folder with Openpyxl. How can I select multiple files in a folder using python for example I am coding using colab and I would like to read several txt file into the system. askopenfilename() In Python 3 use the tkinter. I'm making a crossplatform application, and I have the user give a directory using the askdirectory() method in Tkinter's tkinter. e. Or you can run script with parameter in terminal which open askdirectory or askopenfilename - but probably this is not good solution for you. import os arr = os. txt" file_path = I'm trying to simply get a file name from the user by tkinter. askopenfilename() because if the user is supposed to copy exact number of files overall (defined by user input in self. xlsx in the same directory where I have python files,not in DirectoryName – Jane. askopenfilenames(parent=root, title='Choose a file') print root. Is this even possible? I tried like this, but instead it open up the directory of my python project. argv[0])) This does not work if you are running from another Python script in another directory, for example by using execfile in 2. You may wish to start with an easier problem: can you write a Python program that opens and prints a specific file, say /etc/passwd or some other simple, known-to-exist, file? Python tkinter askopenfilename() not opening and responding. All common OS come with these three dialogs, for example the "Save As" dialog in KDE: I am writing a small program to enter a file name in an entry dialog in python tkinter. It is preferable to use os. jpg, but instead I'm getting <_io. Is it possible for you to work in a newer version of python? Or do you have to learn 2. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company list in the current directory. I'm making a program that you use the askopenname file dialog to select a file, which I then want to save the directory to a string so I can use another function (which I This article covers file-handling topics like opening a file using the askopenfilename method, saving the file using the asksaveasfilename method, and selecting a directory using the askdirectory methods in Python. I want to note the address of the files which are in different directories I have tried using askopenfilenames() file dialog and askopenfilename(,multiple=True) but they haven't allowed me to select multiple files from different directories. xlsx")]) However, I want to choose either xlsx or xls files. Can anyone help? I want to write a python GUI through Tkinter to read the directory of a csv file. loadmat. 6 (IDK, ask RedHat) Running the following code produces the subsequent results. 7. However, to ask the user for the directory, I'm not sure if I have to use Tkinter I will note that for those that are trying to do a "Get-Command python" or a "where python" you might well get something like "C:\Users\username\AppData\Local\Microsoft\WindowsApps\python. Puedes valorar ejemplos para ayudarnos a mejorar la calidad de los ejemplos. filedialog to choose the file in Mac. If pathlib. listdir() Looking in a directory. Share. askdirectory module. realpath() method in Python is used to get the canonical path Saving an uploaded image to a local directory using Tkinter combines the graphical user interface capabilities of Tkinter with the functionality of handling and storing images in Python. How can you add an option so that you can select a folder or directory instead of a file extension type. Related. Learn more about Labs. filedalog. Below is the code snippet I am using: import tkinter as tk from tkinter import filedialog, Button root = tk. Getting folder path with Python Tkinter tkFileDialog. Also, title (window title) and initialdir (starting directory) are specified as arguments. Nothing more. In this tutorial, you’ll learn how to customize filedialog. I know you can use 'askopenfile' but i wanted to get the name first so it could be displayed in an Entry box in my tkinter window, then the user press 'Use this file' and it would then open. getcwd() # use os. You can find the issue on their tracker, and there's a workaround in the comments (I have not personally tried this workaround because I'm on Linux, which returns a proper tuple). Ask Question Asked 12 years, 6 months ago. exportFile = tkFileDialog. The askopenfilename() also supports other useful In Python those functions are accessible through the tkinter. inpath = askdirectory() # To open entire folder Path = askopenfilename() # Open single file root. chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os In other words if I pass off the folder to someone containing a . I don't need a UI, but right now I'm prompting the user for the file to parse using raw_input which is most unfriendly, especially because the user can't copy/paste the path. Tk() main_win. wherever you opened your terminal, or wherever the executable is located if launched by the desktop on Windows, or usually the home I am trying to build a Tkinter UI with a button where the user chooses a main file and based on information in that file, the script would get some information about some secondary files. The I was going to add this just to be silly, but also because it shows newcomers the potential usefulness of aliasing functions and/or imports. Path(). If the user selects "Cancel", I want the program to display an appropriate message and exit the program. The idea is to have the user click on the select file button which would open the dialog box then once the user selected a file, save the file path to the variable y so that i can use it elsewhere in my code. I would like to achieve the same with the "Downloads" folder. 0. These are the top rated real world Python examples of tkinter. I do my first stumbling in Python/Tkinter. After I use askopenfilename to get a filename by click a button, how can I show that filename in an Entry in python. I have used multiple suggestions given on here but they don't seem to work, the only thing that works is when I manually enter the username in below line of code starting with root = filedialog then the folder opens up in the C:\Users\username\Documents I already found this question that suggests to use os. dirname(filename)) I am working with a Macbook programming python. askopenfilename dialog title, set initial directories, specify file types, and much more. askopenfile (mode = 'r', ** options) ¶ tkinter. cbrs bpz xedans wsuow nfj sssu nakziq iylj qif lcasph